The mass of magnesium in [tex]6.02 \times 10^{24}[/tex] atoms is 240 g.
Answer: Option A
Explanation:
First, we have to convert the atoms to moles of magnesium.
We know that [tex]6.02 \times 10^{24}[/tex] atoms are present in 1 mole of magnesium. So,
[tex]\text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }[/tex]
[tex]6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }[/tex]
Thus,
[tex]Mass of M g= molar mass of M g \times No. of moles of M g[/tex]
[tex]\text { Mass of } M g=24 \times 10=240 g[/tex]
Thus, 240 g of Magnesium is present in [tex]6.02 \times 10^{24}[/tex] atoms.
