Ammonia gas can be prepared by the following reaction:CaO(s) + 2NH4Cl(s) ------> 2NH3(g) + H2O(g) + CaCl2(s)In an experiment, 26.5 g of ammonia gas, NH3, is produced when it was predicted that 54.9 g of NH3 would form.What is the theoretical yield of NH3? What is the actual yeild of NH3? What is the percent yeild of NH3?

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Answer:

The theoretical yield of NH3 = 54.9 grams

The actual yield of NH3 = 26.5 grams

The % yield = 48.3 %

Explanation:

Step 1: Data given

Mass of NH3 produced = 26.5 grams

54.9 grams of NH3 was predicted

Step 2: The balanced equation:

CaO(s) + 2NH4Cl(s) → 2NH3(g) + H2O(g) + CaCl2(s)

Step 3: Theoretical yield

The theoretical yield, is the amount of NH3 that is predicted to be formed = 54.9 grams

The actual yield is the amount of NH3 that actual has been formed = 26.5 grams

% yield = (actual yield / theoretical yield)*100 %

% yield = (26.5 grams / 54.9 grams) * 100%

% yield = 48.3 %

The percentage yield of ammonia is 48.6 %. Percentage yield can be calculated by the ratio of actual yield to theoretical yield.

How to calculate percentage yield?

Percentage yield can be calculated by the ratio of actual yield to theoretical yield.

Theoretical yield is the predicted value of the produced compound.

[tex]\bold {{Percent Yield} = \frac{{Actual Yield}}{{Theoretical Yield}} \times 100 \%}[/tex]

Put the values in the formula,

[tex]\bold {{Percent Yield} = \dfrac{{26.5}}{54.9} \times 100 \%}\\\\\bold {{Percent Yield} = 48.3 \%}[/tex]

Therefore, the percentage yield of ammonia is 48.6 %.

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