Answer:
10T
Explanation:
The radius (r) of a charged particle that moves in a circle in a magnetic field is:
[tex] r = \frac{mv}{qB} [/tex] (1)
where m: is the particle's mass, v: is the speed of the particle, q: is the charge of the particle and B: is the strength of the magnetic field.
The period (T) of the charged particle is related to its radius by the following equation:
[tex] T = \frac{2 \pi r}{v} [/tex] (2)
By entering equation (1) into (2) we have:
[tex] T = \frac{2 \pi}{v} \cdot \frac{mv}{qB} = \frac{2\pi m}{qB} = 10 \cdto \frac{2\pi m}{qB} = 10T [/tex] (3)
Therefore, from equation (3) we have that if the mass increases by a ten factor, the period will increase in the same factor since they are proportional to each other.
I hope it helps you!
