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What is the concentration of NO3- ions in a solution prepared by dissolving 30 g of Ca(NO3)2 in enough water to produce 300. mL of solution.a.0.305 M b.0.609 M c.0.806 M d. None of these

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Answer:

d. None of these

Explanation:

The molar mass of Ca(NO₃)₂ is 164.088 g/mol. The moles corresponding to 30 g are:

30 g × (1 mol/164.088 g) = 0.183 mol

There are 2 moles of NO₃⁻ in 1 mole of Ca(NO₃)₂. The moles of NO₃⁻ in 0.183 moles of Ca(NO₃)₂ are 2 × 0.183 mol = 0.366 mol

The molar concentration of NO₃⁻ is:

0.366 mol/0.300 L = 1.22 M

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