There is typo error in the question. The total number of coins will be 15.
Answer:
There are 6 nickels and 9 quarters.
Step-by-step explanation:
Let 'n' be number of nickels and 'q' be number of quarters.
Given:
Marcos has 15 coins in total.
Marcos has 3 more quarters than nickels.
So, as per question,
Total coins = Number of nickels + Number of quarters.
Framing in equation form, we get:
[tex]n+q=15[/tex] ------------------ (1)
Now, Marcos has 3 more quarters than nickels. So, framing in equation form, we get:
[tex]q=3+n[/tex] -------------------- (2)
Substitute the value of 'q' from equation (2) to equation (1). This gives,
[tex]n+3+n=15\\2n=15-3\\2n=12\\n=\frac{12}{2}=6[/tex]
Therefore, the number of nickels are 6.
Now, number of quarters = 6 + 3 = 9
So, there are 6 nickels and 9 quarters.
