Respuesta :
Answer:
(a) [tex]p = 4.9\times10^{-21}[/tex]
(b) [tex]L = 2.29 \times 10^{-23}[/tex]
Explanation:
In order to find the linear and angular momentum, we should first find the velocity of the particle.
The relationship between force, velocity and magnetic field is
[tex]\vec{F}_B = q\vec{v} \times \vec{B}[/tex]
This force is the net force applied to the charge, and by Newton's Second Law:
[tex]\vec{F}_{net} = \frac{mv^2}{R}[/tex]
By combining the two equations:
[tex]qvB = \frac{mv^2}{R}\\v = \frac{qBR}{m} = \frac{(6.4\times10^{-19})(1.65)(4.68\times 10^{-3})}{m} =\frac{4.9\times10^{-21}}{m}[/tex]
Now we can calculate the momentum.
(a)
[tex]p = mv = m\frac{4.9\times10^{-21}}{m} = 4.9\times10^{-21}[/tex]
(b)
[tex]L = mvR = m\frac{4.9\times10^{-21}}{m}(4.68\times 10^{-3}) = 2.29 \times 10^{-23}[/tex]
(a) The linear momentum of the charge is 4.94 x 10⁻²¹ kgm/s.
(b) The angular momentum of the charge is 2.31 x 10⁻²³ kgm²/s.
Velocity of the charge
The velocity of the charge is calculated as follows;
[tex]F_C = F\\\\qvB = \frac{mv^2}{r} \\\\v = \frac{qBr}{m} \\\\v = \frac{6.4 \times 10^{-19} \times 1.65 \times 4.68\times 10^{-3} }{m} \\\\v = 4.94 \times 10^{-21} \ /m[/tex]
Linear momentum
The linear momentum of the charge is calculated as follows;
P = mv
P = 4.94 x 10⁻²¹/m x m
P = 4.94 x 10⁻²¹ kgm/s
Angular momentum of the charge
The angular momentum of the charge is calculated as follows;
L = Pr
L = 4.94 x 10⁻²¹ x 4.68 x 10⁻³
L = 2.31 x 10⁻²³ kgm²/s
Learn more about angular momentum here: https://brainly.com/question/7538238
