Answer:
The answer to your question is 1.45 moles of PbI₂
Explanation:
Reaction
2KI + Pb(NO₃)₂ ⇒ PbI₂ + 2 KNO₃
Process
1.- Check if the reaction is balanced
Reactants Elements Products
2 Potassium 2
2 Iodine 2
1 Lead 1
2 Nitrogen 2
6 Oxygen 6
This reaction is balanced
2.- Calculate the moles of Lead (II) iodine using proportions and the coefficients of the balanced reaction.
2 mol of KI ------------------ 1 mol of PbI₂
2.89 mol of KI --------------- x
x = (2.89 x 1) / 2
x = 1.45 moles of PbI₂
