Respuesta :
Answer:
C. [tex]P(F|Q) = \dfrac{11}{51}[/tex]
Step-by-step explanation:
it is to be noted that the question is only asking for the probability of the 2nd card given that the first card was queen [tex](P(F|Q))[/tex], and not asking for the probability of 1st card to be queen and 2nd card to be faced card[tex]P(Q\,\text{and}\,F)[/tex]
we can represent it in an expression:
[tex]P(Q\,\text{and}\,F) = P(Q)P(F|Q)[/tex]
here P(Q) is the first event: Queen
and P(F|Q) is the second event: Faced card, given that the Queen is taken
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we only need to know what is P(F|Q), and that can be found directly found:
let's start with P(Q), what is the probability that the first card is a Queen? Well, there are 4 queens in a standard deck of 52 cards, so the probability should be:
[tex]P(Q) = \dfrac{4}{52}[/tex]
now we have taken our queen, but we haven't put it back in the deck. so the amount of cards in the deck now are 51.
let's calculate P(F|Q),now that one queen is taken out, what is the probability of the next card to be a faced card? Well, in a standard deck there are 12 faced cards, but in our case one queen is already taken out, so there are 11 faced cards in our deck!
[tex]P(F|Q) = \dfrac{11}{51}[/tex]
and this our answer!
