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A 0.5-kg cart moving on a horizontal frictionless track at 0.6 m/s hits a solid bumber and bounces back with a speed of 0.4 m/s. The impulse on the cart is?

Respuesta :

Answer:

I = 0.5 kg.m/s

Explanation:

given,

mass of the cart = 0.5 Kg

initial speed of cart, u=  0.6 m/s

final speed of cart, v = - 0.4 m/s

impulse of the cart = ?

impulse is equal to the change of the momentum of the cart.

I = m u - m v

I = m (u - v)

I = 0.5 (0.6 - (-0.4))

I = 0.5 x 1

I = 0.5 kg.m/s

impulse on the cart is equal to 0.5 kg.m/s

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