Respuesta :
Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
[tex]Rate = k[AB]^2[/tex]
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
[tex]\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt[/tex]
Where, [tex][A_0][/tex] is the initial concentration = 1.50 mol/L
[tex][A_t][/tex] is the final concentration = 1/3 of initial concentration = [tex]\frac{1}{3}\times 1.50\ mol/L[/tex] = 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-
[tex]\frac{1}{0.5} = \frac{1}{1.50}+0.2t[/tex]
[tex]\frac{1}{1.5}+0.2x=\frac{1}{0.5}[/tex]
[tex]t = 6.66\ s[/tex]
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
