Answer:
Step-by-step explanation:
The cartesian coordinates is (-2, 2)
So, x = -2 and y = 2
So, r Cos θ = x and r Sin θ = y
r Cos θ = - 2 .... (1)
r Sin θ = 2 .... (2)
Squarring equation (1) and (2) and add
[tex]r^{2}{Sin^{2}\theta +Cos^{2}\theta }= (-2)^{2}+2^{2}[/tex]
[tex]r^{2}=8[/tex]
r = 2.83
Divide equation (2) by equation (1), we get
[tex]tan\theta = - 1[/tex]
θ = 3π/4
So, the polar coordinates are (2.83 Cos 3π/4, 2.83 Sin 3π/4)
