Answer:
0.97566 m/s
Explanation:
[tex]m_1[/tex] = Mass of cannon = 2260 kg
[tex]v_1[/tex] = Velocity of cannon
[tex]m_2[/tex] = Mass of ball = 21 kg
[tex]v_2[/tex] = Velocity of ball = 105 m/s
As the momentum of the system is conserved we have
[tex]m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{21\times 105}{2260}\\\Rightarrow v_1=0.97566\ m/s[/tex]
The velocity of the cannon is 0.97566 m/s