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A study of how much corn was produced in a field depending on the planting density compared the yield from fields planted with 40000 plants per hectare to the yield from fields planted with 60000 plants per hectare.
1. What is the ratio of the distance between the corn plants in the more-densely-planted field to the distance between the corn plants in the less-densely-planted field?

Respuesta :

Answer:

[tex] \frac{d_2}{d_1} =\frac{\sqrt{6}}{\sqrt{4}}=\sqrt{\frac{6}{4}} = \frac{\sqrt{6}}{2}= 1.225[/tex]

Or in the other way:

[tex] \frac{d_1}{d_2} =\frac{\sqrt{4}}{\sqrt{6}}=\sqrt{\frac{4}{6}} = \frac{\sqrt{6}}{3}= 0.816[/tex]

Explanation:

For this case we need to remember that hectare is a measure of area. And we have the following ratios:

[tex] r_1 =40000 \frac{plants}{acre}[/tex]

We can convert this into [tex]plants/m^2[/tex]

[tex] r_1 = 40000 \frac{plants}{acre} *\frac{1 acre}{10000 m^2}=4 \frac{plants}{m^2}[/tex]

[tex] r_2=60000 \frac{plants}{acre}[/tex]

We can convert this into [tex]plants/m^2[/tex]

[tex] r_2 = 60000 \frac{plants}{acre} *\frac{1 acre}{10000 m^2}=6 \frac{plants}{m^2}[/tex]

By dimensional analysis we assume that [tex] A = L^2[/tex] we can find the ratio in terms of distance like this:

[tex] d_1 =\sqrt{4}= 2 \frac{\sqrt{plants}}{m}[/tex]

[tex] d_2= \sqrt{6}= 2.449 \frac{\sqrt{plants}}{m} [/tex]

And if we find the ratios in terms of distance we got:

[tex] \frac{d_2}{d_1} =\frac{\sqrt{6}}{\sqrt{4}}=\sqrt{\frac{6}{4}} = \frac{\sqrt{6}}{2}= 1.225[/tex]

Or in the other way:

[tex] \frac{d_1}{d_2} =\frac{\sqrt{4}}{\sqrt{6}}=\sqrt{\frac{4}{6}} = \frac{\sqrt{6}}{3}= 0.816[/tex]

Based on the data provided, the ratio of the distance between the corn plants in Field 2 to the distance between the corn plants Field 1 is 1.22.

What is the relationship between hectare and square metre?

To convert between hectare and square metre, the conversion factor is:

  • 1 hectare = 10000 square metre

Thus the densities of the fields in per square metre is as follows:

Density of Field 1 = 40000/10000 = 4 plants per square metre

Density of Field 1 = 60000/10000 = 6 plants per square metre

Assuming that the field is a square;

  • Distance = √area

Distances between plants in of Field 1 = √4

Distances betwwen plants in Field 2 = √6

Ratio of distances in Field 2 and distances in Field 1 is given as:

Ratio = √6/√4 = 1.22

Therefore, the ratio of the distance between the corn plants in the more-densely-planted Field 2 to the distance between the corn plants in the less-densely-planted Field 1 is 1.22.

Learn more about ratios at: https://brainly.com/question/573032