Respuesta :
This question is an incomplete question, here is a complete question.
Perform the following calculation. Report the answer using the proper number of significant figures.
[tex]\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}=?[/tex]
Answer : The answer will be, [tex]3.46J/g.K[/tex]
Explanation :
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
The rule apply for the multiplication and division is :
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
The rule apply for the addition and subtraction is :
The least precise number present after the decimal point determines the number of significant figures in the answer.
The given expression is,
[tex]\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}[/tex]
[tex]\frac{1.012\times 10^{-3}J}{(0.025456g)\times (0.0115)K}[/tex]
[tex]\Rightarrow 3.4569J/g.K[/tex]
In the given expression, 1.012 has 4 significant figures, 0.025456 has 5 significant figures and 0.0115 has 3 significant figures. From this we conclude that 3 is the least significant figures in this problem. So, the answer should be in 3 significant figures.
Thus, the answer will be [tex]3.46J/g.K[/tex]
