Answer:
Final temperature = 6.00 °C
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
[tex]\Delta H=m\times C\times \Delta T[/tex]
Where,
[tex]\Delta H[/tex] is the enthalpy change
m is the mass
C is the specific heat capacity
[tex]\Delta T[/tex] is the temperature change
Thus, given that:-
Mass of water = 200.0 g
Specific heat = 4.18 J/g°C
Let final temperature be x °C
[tex]\Delta T=x-20.0\ ^0C[/tex]
[tex]\Delta H[/tex] = -11.7 kJ (Negative sign as heat is lost)
Also, 1 kJ = 1000 kJ
[tex]\Delta H[/tex] = -11700 J
So,
[tex]-11700=200.0\times 4.18\times (x-20.0)[/tex]
[tex]x=\frac{1255}{209}\\\\x=6.00\ ^0C[/tex]
Final temperature = 6.00 °C
