Answer:
1. [tex]\frac{\sqrt{3}}{2}[/tex]
2. 0.5
3. 0.5
4. [tex]\frac{\sqrt{3}}{2}[/tex]
5. 0.5
6. 0.5
Step-by-step explanation:
Here we have to match the trigonometric functions with their values.
Now,
(1) [tex]\sin \frac{\pi }{3} = \sin 60^{\circ} = \frac{\sqrt{3}}{2}[/tex]
(2) [tex]\sin \frac{\pi }{6} = \sin 30^{\circ} = 0.5[/tex]
(3) [tex]\cos \frac{\pi }{3} = \cos 60^{\circ} = 0.5[/tex]
(4) [tex]\cos \frac{\pi }{6} = \cos 30^{\circ} = \frac{\sqrt{3}}{2}[/tex]
(5) [tex]\cos \frac{5\pi}{3} = \cos (2\pi - \frac{\pi}{3}) = \cos \frac{\pi}{3} = \cos 60^{\circ} = 0.5[/tex]
(6) [tex]\sin \frac{5\pi}{6} = \sin (\pi - \frac{\pi}{6}) = \sin \frac{\pi}{6} = \sin 30^{\circ} = 0.5[/tex]
{Since, [tex]\sin (\pi - \theta) = \sin \theta[/tex] and [tex]\cos (2\pi - \theta) = \cos \theta[/tex]} (Answer)
