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A club volleyball league allows only the top 5% of athletes who try out to be part of the team. If the team tryout scorecard has a mean of 250 and a standard deviation of 15, which of the following can be used as a minimum qualifying score to join the volleyball league?

A. 13
B. 237
C. 251
D. 274

Respuesta :

Answer:

D. 274

Step-by-step explanation:

A normal distribution of the scores is assumed. In the figure attached, the standard normal distribution table is shown.

If only top 5% of athletes are part of the team, then we need to find the value of the table which has a probability of 95%, that value is between 1.64 and 1.65, so we interpolate it as 1.645. The table was made for a variable with mean = 0 and standard deviation (sd) equal to 1, therefore to refer the result to our variable we compute:

1.645 = (x - mean)/sd

x = 1.645*sd + mean

x = 1.645*15 + 250 ≈ 274

So, 95% of the scores are below 274, then 274 is the minimum qualifying score

Ver imagen jbiain

Answer:

274

Step-by-step explanation: