HELP PLEASE!!!!

A tennis ball is hit with a racket. Its speed when leaving the racket is 13.5 m/s, if the ball is in the
air for 3.2 seconds, how far did it travel right before hitting the ground (ignore air resistance)?

Respuesta :

The distance travelled by the ball is 43.2 m

Explanation:

The motion of the ball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

Here, we want to find the (horizontal) distance travelled by the ball before hitting the ground. Therefore, we can just consider the horizontal motion of the ball.

Since it is a uniform motion, we can write:

[tex]v=\frac{d}{t}[/tex]

where

v = 13.5 m/s is the horizontal speed

t = 3.2 s is the time of flight

Solving for d, we find

[tex]d=vt=(13.5)(3.2)=43.2 m[/tex]

Learn more about projectile motion:

brainly.com/question/8751410

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