Respuesta :
Answer:
[tex]z = 0.56[/tex]
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Find z such that 29 % 29% of all observations from a standard normal distribution are greater than z .
This is the value of Z which has a pvalue of 1-0.29 = 0.71.
Looking at the z table, we have that this is [tex]z = 0.56[/tex].
