The question is incomplete, the complete question is :
Calculate the approximate number of atoms in a bacterium. Assume the average mass of an atom in the bacterium is 10 times the mass of a hydrogen atom.(Hint the mass of hydrogen atom is on order of [tex]10^{-27} [/tex] kg and the mass of bacterium is on order of [tex]10^{-15}[/tex] kg
Answer:
The total numbers of atom in bacterium are [tex]10^{12}[/tex].
Explanation:
Mass of hydrogen atom, m= [tex]10^{-27}[/tex] kg
Mass of bacterium , M= [tex]10^{-15}[/tex] kg
Mass of bacterium atom =m'
Given ; [tex]m' =10\times m[/tex]
[tex]m'=10\times 10^{-27} kg=10^{-26} kg[/tex]
let the number of atoms in bacterium be N
[tex]m'\times N=M[/tex]
[tex]N=\frac{M}{m'}=\frac{10^{-15} kg}{10^{-27} kg}=10^{12}[/tex]
The total numbers of atom in bacterium are [tex]10^{12}[/tex].
