Answer:
Average speed of passenger jet
[tex]s = 471.48\ mi/hr[/tex]
Explanation:
Let s be the average speed of the passenger jet.
Given:
Distance from one airport to another airport [tex]d = 1273\ mi[/tex]
Total time taken [tex]t = 2.7\ hr[/tex]
We need to find the average speed of the passenger jet.
Solution:
Average speed formula:
The ratio of the total distance travelled by the object to the time taken to cover that distance.
[tex]Average\ speed = \frac{Total\ distance\ travelled}{Total\ time\ taken}[/tex]
[tex]s = \frac{d}{t}[/tex]
Substitute total distance and time value in above equation.
[tex]s = \frac{1273}{2.7}[/tex]
[tex]s = 471.48\ mi/hr[/tex]
Therefore, the average speed of the passenger jet is [tex]s = 471.48\ mi/hr[/tex].
