Answer:
9, 10, 11
Step-by-step explanation:
Note there is a difference of 1 between consecutive integers.
Let n be the smallest integer then n + 1 and n + 2 are the next 2 integers, then
5(n + n + 1 + n + 2) = 150 ( divide both sides by 5 )
3n + 3 = 30 ( subtract 3 from both sides )
3n = 27 ( divide both sides by 3 )
n = 9 and n + 1 = 9 + 1 = 10, n + 2 = 9 + 2 = 11
The 3 consecutive integers are 9, 10, 11
Answer:
Step-by-step explanation:
Let the numbers be x, x +1, x + 2
The sum will be = { x + x +1 +x + 2}
= 3x + 3
And 5times the sum is 150
5(3x + 3) = 150
Opening bracket
15x + 15 = 150
Collecting like terms
15x = 150 - 15
15x = 135
Dividing each term by 15
15x/15 = 135/15
x = 9
: the numbers are x, x +1, x + 2
9, 9 + 1, 9 + 2
There are 9, 10 and 11
