Answer:
V = 40 m/s^2
Explanation:
horizontal force ,[tex]F_h = 40N[/tex]
mass, m = 6kg
time, t = 10s
frictional force, [tex]F_f = 16N[/tex]
net force [tex]F = F_h - F_f = ma[/tex]
40N - 16N = 6 x a (1)
in this case you apply the equation of motion
the block is at rest, initial velocity is, U = 0
final velocity is is what we are looking for, V
[tex]a = \frac{V - U}{t}[/tex]
since U is 0 we have
a = V/t (2)
subsituting (2) into (1)
[tex]24 = \frac{6*V}{t}[/tex]
[tex]24 = \frac{6*V}{10}[/tex]
cross multiply
240 = 6 x V
divide both sides by 6
V = 40 m/s^2
