Answer:
B. The perimeter of the given figure is 58 units.
Step-by-step explanation:
Here, the attachment is missing.
For the reference, i am attaching the correct figure specified in the question.
Now here let us assume the length of each card = m units
The width of each card = n units
Area of the given figure = 180 sq units
Here, consider the given figure:
Here, the length of the rectangle = width of 4 cards
= 4 x ( Width of 1 card) = 4 x ( n) = 4 n
Also, Here, the length of the rectangle = width of 1 card + Length of 1 card
= m + n
AREA OF THE RECTANGLE = LENGTH x WIDTH
⇒ 180 = 4 n ( m + n) .... (1)
Also, area of 1 card = Length x width = m x n = mn
So, area of 9 such cards = 9 x (m n) = 9 n m
AREA OF 9 RECTANGLES = AREA OF THE FIGURE
⇒ 9 n m = 180 .... (2)
Now, solving (1 ) and (2) fro values of m ,n we get:
Divide (1) by (2), and solve , we get: n = 5 units
Solving for m: 9 ( 5) m = 180 , ⇒ m = 4 units
Now, the perimeter of figure = Sum of all sides
= 2 ( m+ n) + 4n + 5m = 2(9) + 4(5) + 5(4) = 18 + 20 + 20 = 58
Hence the perimeter of the given figure is 58 units.
