The electric force between the comb and the hair is [tex]5.06\cdot 10^7 N[/tex]
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the two charges
r is the separation between the two charges
In this problem, we have:
[tex]q_1 = 0.003 C[/tex] is the charge on the comb
When the comb is brought near the hair, the hair gains an equal (and opposite) charge, therefore the charge on the hair is (in magnitude)
[tex]q_2 = 0.003 C[/tex]
The distance is
r = 0.04 m
Substituting, we find the force between them:
[tex]F=(8.99\cdot 10^9)\frac{(0.003)(0.003)}{0.04^2}=5.06\cdot 10^7 N[/tex]
And the force is attractive, since the two charges have opposite sign.
Learn more about electric force:
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