Respuesta :
Answer:
[tex]H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}[/tex]
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Only the species which are present in aqueous state dissociate.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a)
The balanced molecular equation will be,
[tex]HNO_2_{(aq)}+NaOH_{(aq)}\rightarrow H_2O_{(l)}+NaNO_2_{(aq)}[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]H^+_{(aq)}+NO_2^-_{(aq)}+Na^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+Na^+_{(aq)}+NO_2^-_{(aq)}[/tex]
In this equation the species present are, [tex]Na^+\text{ and }NO_2^-[/tex] are the spectator ions.
Hence, the net ionic equation contains specie is
[tex]H^+_{(aq)}+OH^{-}_{(aq)}\rightarrow H_2O_{(l)}[/tex]
The net ionic equation for the reaction has been, [tex]\rm H^+\;+\;OH^-\rightarrow\;H_2O[/tex].
Thus, option C is correct.
The net ionic equation has been given as formation of ions involved in the reaction and the formed products.
Net Ionic Equation
The titration of nitrous acid and sodium hydroxide has been given in chemical equation as:
[tex]\rm HNO_2\;+\;NaOH\;\rightarrow\;H_2O\;+\;NaNO_2[/tex]
The ionic equation has been:
[tex]\rm H^+\;+\;NO_2^-\;+\;Na^+\;+\;OH^-\rightarrow\;H_2O\;+\;Na^+\;+\;NO_2^-[/tex]
In the net ionic equation, the ions same on the product and reactant side are eliminated.
Thus, the net ionic equation for the reaction has been:
[tex]\rm H^+\;+\;OH^-\rightarrow\;H_2O[/tex]
Thus, option C is correct.
For more information about net ionic equation, refer to the link:
https://brainly.com/question/22885959
