Answer:
0.2
Explanation:
Horizontal force=100N
Weight of crate=500 N
We have to find the coefficient of kinetic friction.
Normal ,N=Weight=500N
Horizontal force,[tex]F_x=\mu_kN[/tex]
Where [tex]F_x[/tex]=Horizontal force
N=Normal force
[tex]\mu_k[/tex]=Coefficient of kinetic friction
Substitute the values in the formula
[tex]100=\mu_k(500)[/tex]
[tex]\mu_k=\frac{100}{500}=0.2[/tex]
Hence, the coefficient of kinetic friction =0.2
The coefficient of kinetic friction is 0.2.
The velocity is constant.
Therefore,
acceleration = 0 m/s²
Net force = 0
Therefore,
100 - f = ma
100 - f = m × 0
100 - f = 0
f = 100Newton
f = μN
where
N= normal force
μ = coefficient of kinetic friction
100 = 500μ
μ = 100 / 500
μ = 0.2
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