Answer
given,
initially rotating speed = 130 rad/s
final rotating speed = 0 rad/s
constant acceleration = 3 rad/s²
a) using equation of rotating acceleration
[tex]\omega_f = \omega_i + \alpha t[/tex]
[tex]0 = 130 - 3 \times t[/tex]
3 t = 130
t = 43.33 s
time does the disk take to stop is equal to 43.33 s
b) again using equation of rotation
[tex]\theta = \omega_i t + \dfrac{1}{2}\alpha t^2[/tex]
[tex]\theta = 130\times 43.33 - \dfrac{1}{2}\times 3 \times 43.33^2[/tex]
[tex]\theta = 2817 rad[/tex]
angle does the disk rotate during that time is equal to 2817 rad
