Answer:
6.67 moles
Explanation:
Given that:-
Moles of hydrogen gas produced = 10.0 moles
According the reaction shown below:-
[tex]2Al + 6HCl\rightarrow 2AlCl_3 +3H_2[/tex]
3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.
Also,
1 mole of hydrogen gas are produced when [tex]\frac{2}{3}[/tex] moles of aluminium undergoes reaction.
So,
10.0 moles of hydrogen gas are produced when [tex]\frac{2}{3}\times 10.0[/tex] moles of aluminium undergoes reaction.
Moles of Al needed = [tex]\frac{2}{3}\times 10.0[/tex] moles = 6.67 moles