Answer:
Therefore the equation of the line through ( -10 , -3 ) and ( -5 , -1 ) is
[tex]2x-5y=-5[/tex]
Step-by-step explanation:
Given:
We Know that to have an equation of a line which required two points so from the table we will consider two points say,
Let,
point A( x₁ , y₁) ≡ ( -10 ,-3)
point B( x₂ , y₂) ≡ (-5 , -1)
To Find:
Equation of Line AB =?
Solution:
Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula
[tex](y - y_{1} )=(\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} })\times (x-x_{1}) \\[/tex]
Substituting the given values in a above equation we get
[tex](y - (-3) )=(\dfrac{-1-(-3) }{-5-(-10)})\times (x-(-10)) \\[/tex]
[tex](y +3 )=(\dfrac{-1+3) }{-5+10} })\times (x+10) \\[/tex]
[tex](y +3 )=(\dfrac{2}{5})\times (x+10) \\5y+15=2x+20\\2x-5y=-5[/tex] is the required Equation of line.
Therefore the Equation of Line is
[tex]2x-5y=-5[/tex]
