SOMEONE PLEASE HELP ME ASAP PLEASE!!!!
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Answer:
Therefore,
[tex]a_{21}=2[/tex]
Step-by-step explanation:
Given:
[tex]A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right][/tex]
To Find:
a₂₁ = ?
Solution:
Let,
[tex]A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right][/tex]
We require ' a₂₁ ' i.e Second Row First Column Element
So on Comparing we get
∴ [tex]a_{21}=2[/tex]
Therefore,
[tex]a_{21}=2[/tex]