Answer:
1) 0.0099
2) 0.3707
3) 0.4920
Step-by-step explanation:
Since Mean M = 100
Standard deviation S = 15
1) When the IQ score is x= 68
The percentage of that score up to 68 is normally distributed.
P(z<x) = P(z<68)
P(z<68) = P[ (x-M)/S < (68-100)/15]
P(z< -2.13) = 0.0099
This means that about 1 of every 100 will have IQ score of 68 and below.
2) when the IQ score x = 95
P(z<x) = P(z<95)
P(z<95) = P[ (x-M)/S < (95-100)/15]
P(z< -0.33) = 0.3707
This means that about 37 of every 100 have an IQ score of 95 and below.
3) when the IQ score is x = 99.7
P(z<x) = P(z<99.7)
P(z<99.7) = P[ (x-M)/S < (99.7-100)/15]
P(z< -0.02) = 0.4920
This means that 49 of every 100 have an IQ score of 99.7 and below.