Answer:
There are ( 2/8) students who saw ONLY jewelry Section.
Step-by-step explanation:
The number of students who saw the dinosaurs = 5/8
⇒ n(D) = 5/8
The number of students who saw either the jewelry collection or the dinosaurs = 7/8
⇒ n(D U J ) = 7/8
To Find: n (D' ∩ J)
Now,as we know for any two sets A and B:
n(A U B) -n(B) = n(A' ∩ B )
Applying the same property here, we get:
n (D' ∩ J) = n( D U J) - n ( D)
[tex]= (\frac{7}{8}) - (\frac{5}{8} )\\=(\frac{7-5}{8}) = \frac{2}{8}\\ \implies n(D' \cap J) = \frac{2}{8}[/tex]
Hence, there are ( 2/8) students who saw ONLY jewelry Section.
