To solve this problem we will apply the energy conservation equations, for which we have that the potential energy accumulated at a certain height is equivalent to the kinetic energy in the body and that generates a certain movement on it. Kinetic energy can be described as
[tex]KE = \frac{1}{2} mv^2[/tex]
Where,
m = mass
v = Velocity
At the same time,
[tex]PE = mgh[/tex]
Here,
h = Height
g = Gravitational acceleration
As PE = KE, we have that,
[tex]mgh = \frac{1}{2} mv^2 \\h = \frac{v^2}{2g}\\h = \frac{4.9^2}{2(9.8)}\\h = 1.225m[/tex]
Therefore she can swing upward around of 1.225m
