Answer: The required probability is [tex]\dfrac{10}{21}[/tex]
Step-by-step explanation:
Since we have given that
Divisors of 64= 1,2,4,8,16,32,64
Sum would be less than 32
Since it has 7 divisors in total.
If we select any two distinct divisors from first five divisors, the sum will always less than 32.
So, the probability that their sum will be less than 32 is given by
[tex]\dfrac{^5C_2}{^7C_2}\\\\=\dfrac{10}{21}[/tex]
Hence, the required probability is [tex]\dfrac{10}{21}[/tex]
