Answer:
V = 24.7 L
Explanation:
Given data:
Mass of ethylene = 15.0 g
Temperature = 25°C (25+273 = 298 K)
Pressure = 100 KPa ( 100/101 = 0.99 atm)
Volume of water produced = ?
Solution:
Chemical equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
Number of moles of ethylene:
Number of moles = mass / molar mass
Number of moles = 15.0 g/ 28.05 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of ethylene with water.
C₂H₄ : H₂O
1 : 2
0.5 : 2/1×0.5 = 1 mol
Volume of water:
PV = nRT
V = nRT/P
V = 1 mol × 0.0821 atm. L/mol.K ×298 K / 0.99 atm
V = 24.5 atm.L /0.99 atm
V = 24.7 L
