Respuesta :
Answer:
P = 22500 kg.m/s
Explanation:
Mass of particle 1, M = 1500 kg
speed of car in east, v = 30 m/s
Mass of another particle,m = 900 Kg
speed of car in west, v' = 25 m/s
east direction is positive
momentum of the particle when they are a system.
P = P₁ + P₂
P = M v + m v'
P = 1500 x 30 + 900 x (-25)
P = 22500 kg.m/s
The momentum of two particle system is equal to P = 22500 kg.m/s
The momentum of a two-particle system composed of a 1500 kg car moving east at 30 m/s and a second 900 kg car moving west at 25 m/s is 22500 kg. m/s.
Momentum = mass × velocity
Therefore,
First particle(travelling east)
m₁ = 1500 kg
v₁ = 30 m/s
second particles(travelling west)
m₂ = 900 kg
v₂ = 25 m/s
East is the positive side. Therefore,
The momentum of the 2 particles will be
momentum = p₁ + p₂
momentum = (1500 × 30) + (900 × - 25)
momentum = 45,000 - 22,500
momentum = 22500 kg. m/s
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