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A function f is defined by f(x)= 3/17x+2. If x increases by 51, by how much does f(x) increase?

Respuesta :

if x increases by 51, f (x) increases by 9.

Step-by-step explanation:

Given function:

          [tex]f(x)=\frac{3}{17} x+2[/tex]

The above equation would have a constant slope as it seems to be a linear function.  ‘x’, the coefficient of the variable x is the slope of the function. Here,

        [tex]x=\frac{3}{17}[/tex]

The rate of change of the function with respect to x referred as the slope of the function. Thus,

       [tex]slope =\frac{\text { change of } f(x)}{\text { change of } x}[/tex]

        [tex]\frac{\Delta f}{\Delta x}=\frac{3}{17}[/tex]

Given, x increases by 51. So, we have

        [tex]\Delta x=51[/tex]

        [tex]\frac{\Delta f}{51}=\frac{3}{17}[/tex]

Now solve for ΔF,

       [tex]\Delta f=\frac{3}{17} \times 51=3 \times 3=9[/tex]

Thus, we have obtained that if x increases by 51, f (x) increases by 9.