How many molecules are in 28 grams of nitrogen gas in balloons?
a.28 x 6.0 x 10 to the 23rd power molecules nitrogen gas
b.2.0 x 10 to the 23rd power molecules nitrogen gas
c.1.0 x 10 to the 23rd power molecules nitrogen gas
d.6.0 x 10 to the 23rd power molecules nitrogen gas
e.1.2 x 10 to the 24rd power molecules nitrogen gas
f.3.0 x 10 to the 23rd power molecules nitrogen gas

Respuesta :

Answer:

[tex]6.022\cdot 10^{23}[/tex] molecules of nitrogen gas

Explanation:

In order to convert the mass of a given compound into the number of molecules, we need to:

  • identify the number of moles of a given compound dividing its mass by the molar mass, [tex]n = \frac{m}{M}[/tex],
  • multiply the number of moles by the Avogadro's constant which tells us that 1 mole contains [tex]N_A = 6.022\cdot 10^{23}[/tex] molecules.

In this problem:

[tex]m_{N_2} = 28~g[/tex]

[tex]M_{N_2} = 28.01~g/mol[/tex]

The number of particles is then found by:

[tex]N_{N_2} = n_{N_2}\cdot N_A = \frac{m_{N_2}}{M_{N_2}} N_A = \frac{28 g}{28.01 g/mol}\cdot 6.022\cdot 10^{23} mol^{-1} = 6.022\cdot 10^{23}[/tex]