Describe the center and spread of the data using either the mean and standard deviation or the five-number summary. Justify your choice by constructing a histogram for the data. 9, 1, 29, 10, 5, 39, 29, 4, 24, 8, 3, 33, 13, 32, 23, 32, 39, 10 18, 26, 26, 10, 9, 18, 15, 17, 12, 18, 9, 15, 9, 24, 12, 22, 20, 15 Question 2 options: The distribution is symmetric, so use the mean and standard deviation. mean: 17.7, standard deviation: 100 The distribution is skewed, so use the five-number summary. range: 38, median: 16, half of the data are between 9.5 and 25

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Answer:

The distribution is skewed, so use the five-number summary. range: 38, median: 16, half of the data are between 9.5 and 25

Step-by-step explanation:

In the picture attached the histogram is shown. We can see that data is skewed to the right, so we have to use the five-number summary. The range of the data is 39 - 1 = 38 (subtraction of the maximum value to the minimum value); the median is (15 + 17)/2 = 16 (if you order the values, 15 and 17 are in the middle); quartile 1 is 9.25 and quartile 3 is 25.5 (see diagram of box and whisker attached), then half of the data are between those values.

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The spread in the data measures how far the numbers in the data set are away from the mean and the center in the data measures the standard deviation.

The range of the given data is 38.

The median for the given data is 16.

Half of the data are between 9.5 to 25.

Given that,

Describe the center and spread of the data using either the mean and standard deviation or the five-number summary.

9, 1, 29, 10, 5, 39, 29, 4, 24, 8, 3, 33, 13, 32, 23, 32, 39, 10 18, 26, 26, 10, 9, 18, 15, 17, 12, 18, 9, 15, 9, 24, 12, 22, 20, 15.

We have to determine,

Justify your choice by constructing a histogram for the data.

The distribution is symmetric, so use the mean and standard deviation.

According to the question,

The spread in the data measures how far the numbers in the data set are away from the mean, the spread in the data shows the variation.

And the center in the data measures the standard deviation.

The range of the given data is defined as the difference between maximum and minimum numbers.

Range = 39 -1 = 38

The range of the given data is 38.

The median of the given data is given by any two numbers which is given in the data.

The first number is 15, and the second number is 17.

Then,

the median of these two numbers is given by,

[tex]\rm Median =\dfrac{15+17}{2}\\\\Median = \dfrac{32}{2}\\\\Median = 16[/tex]

The median for the given data is 16.

Half of the data are between 9.5 to 25.

For more details refer to the link given below.

https://brainly.com/question/18510715