Answer : The volume of a solution is, [tex]1.7\times 10^2mL[/tex]
Explanation : Given,
Mass of [tex]AgClO_4[/tex] = 75.0 g
Molar mass of [tex]AgClO_4[/tex] = 125 g/mole
Molarity = 3.5 mol/L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }AgClO_4}{\text{Molar mass of }AgClO_4\times \text{Volume of solution}}[/tex]
Now put all the given values in this formula, we get:
[tex]3.5mol/L=\frac{75.0g}{125g/mole\times \text{Volume of solution}}[/tex]
[tex]\text{Volume of solution}=0.17142L=171.42mL=1.7\times 10^2mL[/tex]
Therefore, the volume of a solution is, [tex]1.7\times 10^2mL[/tex]
