Answer:
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is
[tex]Slope=\dfrac{4}{3}[/tex]
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -9 ,-8)
point B( x₂ , y₂ )≡ (-15 ,-16)
To Find:
Slope = ?
Solution:
Slope of Line Segment AB is given as
[tex]Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
Substituting the values we get
[tex]Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}[/tex]
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is
[tex]Slope(AB)=\dfrac{4}{3}[/tex]
The slope of the line that passes through the points (-9, -8)((−15,−16) is 4/3
The slope formula can be represented below:
m = y₂ - y₁ / x₂ - x₁
Therefore,
(-9, -8)(−15,−16)
m = -16 - (-8) / -15 - (-9) = -16 + 8 / -15 + 9
m = - 8 / -6
m = 4 / 3
The slope of the line that passes through the points (-9, -8)(−15,−16) is 4 /3
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