Answer:
The answer to your question is w = [tex]\frac{111}{62} in[/tex]
The equation is below
Step-by-step explanation:
Data
length = l = 3 [tex]\frac{7}{8}[/tex] in
Area = A = 6 [tex]\frac{15}{16} in^{2}[/tex]
width = w
Formula
Area of a rectangle = length x width
Substitution
Equation
[tex]6 \frac{15}{16} in^{2} = 3 \frac{7}{8} w[/tex]
Convert the mixed fractions into improper fractions
[tex]\frac{111}{16} = \frac{31}{8} w[/tex]
Solve for w
[tex]w = \frac{111}{16} / \frac{31}{8}[/tex]
Simplify
[tex]w = \frac{(8)(111)}{(16)(31)}[/tex]
[tex]w = \frac{111}{62} in[/tex]
