Answer:
v = 29.69 m/s
Explanation:
given,
height of the flower pot = 45 m
speed at which it will hit the ground = ?
we know, kinetic energy is equal to
[tex]KE = \dfrac{1}{2}mv^2[/tex]
v is the velocity of the pot.
Potential energy
PE = mgh
using conservation of energy
KE = PE
[tex]\dfrac{1}{2}mv^2=mgh[/tex]
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 45}[/tex]
v = 29.69 m/s
the speed at which pot hit the ground is equal to v = 29.69 m/s
