Answer:
Equation of the perpendicular line will be [tex]y=\frac{1}{2}x-5[/tex].
Step-by-step explanation:
Given question is incomplete ; here is the complete question.
Find the equation of the line that contains the point (6,-2) and is perpendicular to the line y=-2x+8.
Slope of the given line is (-2).
If the slope of the required line is m then,
m × (-2) = (-1) [Slopes of the perpendicular lines when multiplied equals to (-1)]
m = [tex]\frac{1}{2}[/tex]
Now the equation of the line passing through a point (6, -2) with slope [tex]\frac{1}{2}[/tex] will be
y - y' = m(x - x')
y + 2 = [tex]\frac{1}{2}(x-6)[/tex]
[tex]y+2=\frac{1}{2}x-3[/tex]
y = [tex]\frac{1}{2}x-5[/tex]
Therefore, equation of the perpendicular line will be [tex]y=\frac{1}{2}x-5[/tex]
