Answer:
The work required to withdraw the dielectric sheet = 3.84×10⁻⁶ J
Explanation:
Energy Stored in a capacitor = 1/2CV²
E =1/2CV²............................ Equation 1
Where E = Energy stored in the capacitor, C = capacitance of the capacitor, V = potential difference.
Note: The work required to withdraw the dielectric sheet is equal to the energy stored in the capacitor
Given: C = 2.45 nF = 2.45 × 10⁻⁹ F, V = 56 V
Substituting these values into equation 1
E = 1/2(2.45×10⁻⁹)(56)²
E = 1/2(2.45×10⁻⁹)(3136)
E = 1568(2.45×10⁻⁹)
E = 3841.6×10⁻⁹
E = 3.84×10⁻⁶ J.
Thus the work required to withdraw the dielectric sheet = 3.84×10⁻⁶ J
