Answer:the price if one advance ticket is $35
the price of one same day ticket is $40
Step-by-step explanation:
Let x represent the price if one advance ticket.
Let y represent the price of one same day ticket.
The combined cost of one advance ticket and one same-day ticket is $75. It means that
x + y = 75
For one performance, 20 advance tickets and 35 same-day tickets were sold. The total amount paid for the tickets was $2100. It means that
20x + 35y = 2100 - - - - - - - - - 1
Substituting x = 75 - y into equation 1, it becomes
20(75 - y) + 35y = 2100
1500 - 20y + 35y = 2100
- 20y + 35y = 2100 - 1500
15y = 600
y = 600/15 = 40
x = 75 - y = 75 - 40
x = 35
