Answer:
The answer to your question is 4.2 l
Explanation:
Data
Temperature 1 = T1 = 15°C = 288ºK
Pressure 1 = P1 = 2 atm
Volume 1 = V1 = 2 l
Temperature 2 = T2 = 30°C = 303ºK
Pressure 2 = P2 = 1 atm
Volume 2 = V2 = ?
Formula
Combined gas law
[tex]\frac{P1V1}{T1} = \frac{P2V2}{T2}[/tex]
Solve for V2
[tex]V2 = \frac{P1V1T2}{P2T1}[/tex]
Substitution
[tex]V2 = \frac{(2)(2)(303)}{(1)(288)}[/tex]
Simplification
[tex]V2 = \frac{1212}{288}[/tex]
Result
V2 = 4.2l