Respuesta :
Answer:
Number of revolutions = 2.41
Explanation:
According to first equation of motion:
[tex]a=\frac{v-u}{t}[/tex]
Here, a= acceleration
v = final velocity
u = initial velocity
According to question ,
a = ?
v = 21.1 m/s
t = 14.1 s
u = 0 (because object starts from rest)
[tex]a=\frac{v-u}{t}[/tex]
[tex]a=\frac{21.1-0}{14.1}[/tex]
[tex]a=\frac{21.1}{14.1}[/tex]
[tex]a=1.49m/s^{2}[/tex]
According to third equation of motion:
[tex]2as=v^{2}-u^{2}[/tex]
this can also be written as ,
[tex]s=\frac{v^{2}-u^{2}}{2a}[/tex]
s = distance travelled by the object
a = 1.49
[tex]s=\frac{21.1^{2}-0^{2}}{2\times 1.496}[/tex]
[tex]s=\frac{21.1^{2}-0^{2}}{2\times 1.496}[/tex]
[tex]s=\frac{445.2-0}{2.993}[/tex]
[tex]s=\frac{445.2}{2.993}[/tex]
s = 148.79 m
Diameter of a tire = 61.7 cm
To calculate number of turns , divide distance by the diameter
[tex]revolutions = \frac{distance}{diameter}[/tex]
[tex]= \frac{148.79}{61.7}[/tex]
Number of revolutions = 2.41
