Answer:
The two page numbers are 78 and 79.
Step-by-step explanation:
Let's take the page numbers are x and x + 1 .
The produce of the page numbers is 6162
so, x(x + 1) = 6162
[tex]x^{2} + x -6162 = 0[/tex]
Here we have to use the quadratic formula to solve for x.
The quadratic formula, x = [tex]\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}[/tex]
Here a =1, b = 1 and c = -6162
Plugging in the value of a, b and c in the above formula, we get
x = [-1 ± 157] ÷ 2
Let's take the positive value alone since the page number cannot be negative.
x = [-1 + 157] ÷2
x = 78
The next page number x + 1 = 78 + 1 = 79
Therefore, the two page numbers are 78 and 79.
The number of pages in the textbook if the product of the pages is 6162 is 78 and 79 respectively
let
The page number and the pages = x and (x + 1) respectively.
Total pages in the textbook = 6162
product
x × (x + 1) = 6162
x² + x = 6162
x² + x - 6162 = 0
x² + 79x - 78x - 6162 = 0
x(x + 79) - 78(x + 79) = 0
(x + 79) (x - 78) = 0
x + 79 = 0 or x - 78 = 0
x = -79 or x = 78
The pages can not be negative.
So,
x = 78
x + 1 = 78 + 1
= 79
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